The triangle's center of mass, also known as the centroid, is its physical balance point, found at the intersection of its three medians (lines from each vertex to the midpoint of the opposite side).

$$△ABC\approx △CDE$$

$$\frac{ED}{AB}=\frac{CD}{CB}=\frac{1}{2}$$

$$△DES\approx ABS$$

$$\frac{ED}{AB}=\frac{ES}{BS}=\frac{DS}{AS}=\frac{1}{2}$$

Similarly::