92/VB02. problem / Math - Solved Math Problems

MR-92 / 98a. problem

Rationalize the denominator of the fraction:

$\frac{1}{2 + \sqrt{3}}$

$\frac{1}{2 + \sqrt{3}}$

$= \frac{1}{2 + \sqrt{3}} \cdot \frac{2 - \sqrt{3}}{2 - \sqrt{3}}$

$= \frac{2 - \sqrt{3}}{2^{2} - {(\sqrt{3})}^{2}}$

= \frac{2 - \sqrt{3}}{4 - 3}

= \frac{2 - \sqrt{3}}{1}

$2 - \sqrt{3}$

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