Solve the following equation:
1+2x2-21-2x-32+1=0
a=1+2 , b=-21-2 , c=-32+1
x1,2=--21-2±-21-22-4·1+2·-32+12·1+2
x1,2=--2+22±-2+222-4·1+4·2·-32+12·1+2·2
x1,2=2-22±-22+2·-2·22+222-4+42·-32+12+22
x1,2=2-22±4-82+4·2-4·-32+4·1+42·-32+42·12+22
x1,2=2-22±4-82+8--122+4-24+422+22
x1,2=2-22±4-82+8+122-4+24-422+22
x1,2=2-22±322+22
x1,2=2-22±4·4·22+22
x1,2=2-22±2·2·22+22
x1,2=2-22±4·22+22
x1=2-22+422+22
x1=2+222+22
x1=1
x2=2-22-422+22
x2=2-622+22
x2=2-622+22·2-222-22
x2=2·2+2·-22+-62·2+-62·-222·2+2·-22+22·2+22·-22
x2=4-42-122+12·24-42+42-4·2
x2=4-162+244-8
x2=28-162-4
x2=28-4+-162-4
x2=42-7
ax2+bx+c=0
x1,2=-b±b2-4ac2a
x1=1 , x2=42-7