852/VB02. problem / Math - Solved Math Problems

MR-852 / 1b. problem

Simplify the following expression:

${(a - b)}^{0} + 0, 1^{- 2} \cdot 10^{- 1} (a \neq b)$

${(a - b)}^{0} + 0, 1^{- 2} \cdot 10^{- 1}$

$= 1 + {(\frac{1}{10})}^{- 2} \cdot \frac{1}{10^{1}}$

$= 1 + {(\frac{10}{1})}^{2} \cdot \frac{1}{10}$

$= 1 + \frac{100}{1} \cdot \frac{1}{10}$

$= 1 + \frac{100}{10}$

$= 1 + 10$

$= 11$

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