MR-848 / 423e. problem

Using the formula  x1,2=-b±b2-4ac2a for solutions of a quadratic equation ax2+bx+c=0, solve the equation:

4x2-17x+4=0

4x2-17x+4=0

a=4 ; b=-17 ; c=4

x1,2=--17±-172-4·4·42·4

x1,2=17±289-648

x1,2=17±2258

x1,2=17±158

x1=17+158=328

x1=4

x2=17-158=28

x2=14

x1=4 ; x2=14