MR-845 / 423b. problem

Using the formula  x1,2=-b±b2-4ac2a for solutions of a quadratic equation ax2+bx+c=0, solve the equation:

x2-3x-28=0

x2-3x-28=0

a=1 ; b=-3 ; c=-28

 

x1,2=--3±-32-4·1·-282·1

x1,2=3±9+1122

x1,2=3±1212

x1,2=3±112

x1=3+112=142

x1=7

x2=3-112=-82

x2=-4

x1=7 ; x2=-4