372/HK16. problem / Math - Solved Math Problems

MR-372 / 3. problem

Solve the following equation on the set of non-negative real numbers!

$\sqrt{x} = 4^{3}$

Source: Magyarország: Unified final exam for high schools - Mathematics - intermediate level - 03.05.2016. - 3..)

Algebra → Irrational Equations → Négyzetgyököt tartalmazó egyenletek

$\sqrt{x} = 4^{3}$

${(\sqrt{x})}^{2} = {(4^{3})}^{2}$

$x = 4^{6}$

$x = 4096$

Raise the equation to square!

$x = 4096$