MR-371 / 31. példa

Adott az S halmaz: undefined. Határozza meg az A és B halmazokat,

undefined B=y|yS  y22-yS

majd a következő halmazokat: undefined

A=x|xS 2x12-xS
x=02·012-0=012=0S
x=12·112-1=211S
x=22·212-2=410=25S
x=32·312-3=69=23S
x=42·412-4=88=1S
x=52·512-5=107S
x=62·612-6=126=2S
x=72·712-7=145S
x=82·812-8=164=4S
x=92·912-9=183=6S
A=0,4,6,8,9
B=y|yS y22-yS
y=0022-0=0-0=0S
y=1122-1=12-1=1-22=-12S
y=2222-2=42-2=2-2=0S
y=3322-3=92-3=9-62=32S
y=4422-4=162-4=8-2=6S
y=5522-5=252-5=25-102=152S
y=6622-6=362-6=18-6=12S
y=7722-7=492-7=49-142=352S
y=8822-8=642-8=32-8=24S
y=9922-9=812-9=81-182=632S
B=0,2,4
AB=0,4,6,8,90,2,4
AB=0,2,4,6,8,9
AB=0,4,6,8,90,2,4
AB=0,4
AB=0,4,6,8,90,2,4
AB=6,8,9
BA=0,2,40,4,6,8,9
BA=2
PAB=,6,8,9,6,8,6,9,8,9,6,8,9
AB=0,2,4,6,8,9
AB=0,2,4,6,8,9
AB=0,2,4,6,8,9AB=0,4AB=6,8,9BA=0,2,40,4,6,8,9PAB=,6,8,9,6,8,6,9,8,9,6,8,9