Mathematic Problems
343. példa

Calculate the area of the parallelogram if its altitudes are 3 and $2\sqrt{3}$ cm, and the angle $between tham is$ 60°!

$A=12c{m}^{2}$
$\mathrm{sin}\alpha =\frac{{h}_{b}}{a}=\frac{{h}_{a}}{b}$
$\mathrm{sin}60°=\frac{2\sqrt{3}}{a}=\frac{3}{b}=\frac{\sqrt{3}}{2}$
$\frac{2\sqrt{3}}{a}=\frac{\sqrt{3}}{2}$
$\frac{2}{a}=\frac{1}{2}$
$\frac{a}{2}=\frac{2}{1}$
$a=4$
$T=a·{h}_{a}=3·4$
$T=12$
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