248/MR00. problem / Math - Solved Math Problems

MR-248 / 248. problem

Determine the first derivative of the function>:

$y = \ln (3 x^{2} + 2 x - 6)$

$y = \ln (3 x^{2} + 2 x - 6)$

y' = \frac{1}{3 x^{2} + 2 x - 6} \cdot (6 x + 2)

$y' = \frac{6 x + 2}{3 x^{2} + 2 x - 6}$

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