Exercise ID332

Algebra → Logarithm → Logarithm equations
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Evaluate the following expression:

log4x+2×logx2=1

log22x+2×1log2x=1 12log2x+2×1log2x=1 log2x+212=log2x x+212=x /2 x+2=x2 -x2+x+2=0 x1,2=-1±1+8-2 x1,2=-1±3-2 x1=2 x2=-1
x1=2 x2=-1
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