Exercise ID299

Algebra → Roots → Complex exercises
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Prove the truth of equation below.

a3-b3a-b+ab·a-ba-b2=1a>0 ; b>0 

a=x b=y x3-y3x-y+xy·x-yx2-y22=1 x3-y3x-y+xy·x-yx2-y22=1 x-yx2-xy+y2x-y+xy·x-yx-yx+y2=1 x2+y2·1x+y2=1 1=1
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