Exercise ID272

Mathematical analysis → Integration → Basic integrals
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Calculate the integral below.

I=x2+1x2-2x23dx

I=x2+1x2-2x23dx =x4-x2-2x23-x4x23-x2x23-2x23dx =x103-x43-2x-23 I=x103dx-x43dx-2x-23dx =x103+1103+1-x43+143+1-2x-23+1-23+1+C I=313x133-37x73-6x13+C
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