Exercise ID262

Algebra → Irrational Equations → Köbgyököt tartalmazó egyenletek
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Solve the following equation.

x3+2x-33=12x-13

x3+2x-33=12x-13 x3+2x-333=12x-133 x33+3x32·2x-33+3x32x-332+2x-333=12x-1 x+3·x3·2x-33x3+2x-33+2x-3=12x-12 x+3·x3·2x-33·12x-13+2x-3=12x-12 3x2x-312x-13=12x-x-2x-12+3 312x2x-3x-13=9x-9 312x2x-3x-133=93x-13 33·12x2x-3x-1=323x-13 33·3·4x2x-3x-1-36·x-13=0/·134 4x2x-3x-1-32x-13=0 x-14x2x-3-9x-12=0 x-18x2-12x-9x2-2x+1=0 x-18x2-12x-9x2+18x-9=0 x-1-x2+6x-9=0 -x2+6x-9=0/·-1 x2-6x+9=0 a=1 ; b=-6 ; c=9 x1,2=6±-62-4·1·92=6±36-362=6±02 x1=x2=3 x1=1 , x2=3
x1=1 , x2=3
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