Exercise ID260

Algebra → Irrational Equations → Köbgyököt tartalmazó egyenletek
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Solve the following equation.

x3+x+13+x+23=0

x3+x+13=-x+23 x3+x+133=-x+233 x33+3x32·x+13+3x3·x+132+x+133=-x+2 x+3x3·x+13x3+x+13+x+1=-x-2 x3+x+13+x+23=0x3+x+13=-x+23 x+3x3·x+13·x+23-x+23+x+1=-x-2 -3x3·x+13·x+23=-x-x-x-2-1 -3xx+1x+23=-3x-3 -3xx+1x+23=-3x+1/·-13 xx+1x+23=x+1 xx+1x+233=x+13 xx+1x+2=x+13 x1=-1  0=0 x=-1
x=-1
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