Exercise ID227

Mathematical analysis → Derivation → Derivatives of trigonometry functions
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Compute the derivative of the given function below.

y=sinxx3-1

y=sinxx3-1 y'=cosxx2-1·x2-1-x·2xx2-12 =-x2-1x2-12·cos·xx2-1
y'=-x2-1x2-12·cos·xx2-1
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