Exercise ID206

Algebra → Quadratic equations, inequalities and systems of equations → Equations Reducible to Quadratic Form
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Solve the following equation.

2x-3=x+10-1

2x-3=x+10-1 2x-32=x+10-12 2x-3=x+10-2x+10+1 2x+10=x+10+1-2x+3 2x+10=14-x   x 14 2x+102=14-x2 4x+10=196-28x+x2 4x+40=196-28x+x2 196-28x+x2-4x-40=0 x2-32x+156=0 a=1, b=-32, c=156 x1,2=32±-322-4·1·1562=32±4002=32±202 x1=26 ; x2=6 x14 x1=2614  , x2=614  x=6
x=6

x1,2=-b±b2-4ac2a ; ax2+bx+c=0

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