Exercise ID197

Algebra → Quadratic equations, inequalities and systems of equations → Equations Reducible to Quadratic Form
[Level: ] [Number of helps: 1] [Number of pictures: 0] [Number of steps: 18] [Number of characters: 0]

Solve the following equation.

x3+216x3=36-x3

x3+216x3=36-x3 x3+216x3=36-x3 |·x3 x3+216x3·x3=36·x3-x3·x3 x3+216=36x3-x6 x6+x3-36x3+216=0 x6-35x3+216=0 x3=t x6-35x3+216=0  t2-35t+16=0 t2-35t+216=0 t2-35t+216=0   a=1; b=-35; c=216 t1,2=35±352-4·1·2162·1 t1,2=35±1225-8642=35±3612=35±192 t1=35+192=542=27 t2=35-192=162=8 t1=27; t2=8 x13=t1 x13=27  x1=273=3 x23=t2 x23=8  x2=83=2  x1=3 ;  x2=2
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x1=3 ; x2=2
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