Exercise ID146

Algebra → Komplex százmok → Komplex számok összeadása-kivonása
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Calculate the following expression if z1=2-3i and z2=2+3i

z1+z2 ; z1-z2 ; z1·z2 ; z1z2
z1+z2 z1+z2=2-3i+2+3i =22 z1-z2 z1-z2=2-3i-(2+3i) =2-2-3i-3i =-23i z1·z2 z1·z2=(2-3i)(2+3i) =(2)2-(3i)2 =5 z1z2 z1z2=2-3i2+3i =2-3i2+3i·2-3i2-3i =2-3i222-3i2 =2-22·3i+3i22--3 =2-26i-35 =-1-26i5 =-15-26i5
z1+z2=22z1-z2=-23iz1·z2=5z1z2=-15-26i5

i=-1 ; i2=-1

a2-b2=a-ba+b

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