Exercise ID126

Algebra → Komplex százmok → Komplex számok szorzása
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Evaluate the following expression:

(3-4i)(3+4i)

(3-4i)(3+4i) =32-4i2 =9-42·i2 =9-16·-1 =9+16 =25
3-4i(3+4i)=25

a2-b2=a-ba+b

i=-1 ; i2=-1

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